# Line slope calculator 10x-3y=60

**Straight line given by points A[6; 0] and B[9; 10]**

## Calculation:

**Slope-intercept form of line:**y = 3.3333x-20

**Canonical form of the line equation:**10x-3y-60 = 0

**Parametric form of the line equation:**

x = 3t+6

y = 10t ; t ∈ R

**Slope:**m = 3.3333

**Slope angle of line: φ =**73°18'3″ = 1.2793 rad

**X intercept:**x

_{0}= 6

**Y intercept:**y

_{0}= q = -20

**Distance line from the origin:**d

_{0}= 5.747

**The length of the segment AB: |AB| =**10.4403

**Vector: AB =**(3; 10)

**Normal vector: n =**(10; -3)

**Midpoint of the segment AB: M =**[7.5; 5]

**Perpendicular Bisector equation:**3x+10y-72.5 = 0

**Vector OA = (6; 0) ; |OA| = 6**

**Vector OB = (9; 10) ; |OB| = 13.4536**

**Scalar product OA .OB = 54**

**Angle ∠ AOB = 48°46″ = 0.838 rad**