# Line slope calculator 3x+10y=40

**Straight line given by points A[0; 4] and B[10; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.3x+4

**Canonical form of the line equation:**3x+10y-40 = 0

**Parametric form of the line equation:**

x = 10t

y = -3t+4 ; t ∈ R

**Slope:**m = -0.3

**Slope angle of line: φ =**-16°41'57″ = -0.2915 rad

**X intercept:**x

_{0}= 13.3333

**Y intercept:**y

_{0}= q = 4

**Distance line from the origin:**d

_{0}= 3.8313

**The length of the segment AB: |AB| =**10.4403

**Vector: AB =**(10; -3)

**Normal vector: n =**(3; 10)

**Midpoint of the segment AB: M =**[5; 2.5]

**Perpendicular Bisector equation:**10x-3y-42.5 = 0

**Vector OA = (0; 4) ; |OA| = 4**

**Vector OB = (10; 1) ; |OB| = 10.0499**

**Scalar product OA .OB = 4**

**Angle ∠ AOB = 84°17'22″ = 1.4711 rad**